Problem 1

# Creating a list of numbers
numbers = [5, 3, 9, 1, 6, 8]  # A list of integers is created and assigned to the variable "numbers"

# Printing the original list
print(f"Original list: {numbers}")  # This line outputs the original list of numbers

# Accessing and printing the second element in the list (Indexing starts from 0)
print(f"Second element in the list: {numbers[1]}")  # This line outputs the second element in the list

# Modifying the third element in the list
numbers[2] = 10  # The third element in the list (index 2) is changed to 10

# Appending an element to the end of the list
numbers.append(4)  # The append() method adds the value 4 to the end of the list

# Removing an element from the list by value
numbers.remove(1)  # The remove() method removes the first occurrence of the value 1 from the list

# Sorting the list in ascending order
numbers.sort()  # The sort() method arranges the numbers in the list in ascending order

# Reversing the order of elements in the list
numbers.reverse()  # The reverse() method reverses the order of elements in the list

# Printing the modified list
print(f"Modified list: {numbers}")  # This line outputs the modified list of numbers

Problem 2

import math

def worst_case_binary_search_iterations(array_length):
    iterations = math.ceil(math.log2(array_length))
    return iterations
array_length = 30
print(worst_case_binary_search_iterations(array_length)) # Output the worst-case number of iterations

Problem 3

Answer is A